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Week 5 Assignment
In a poll of 600 voters in a campaign to eliminate non-returnable beverage containers, 210 of the voters were opposed. Develop a 92% confidence interval estimate for the proportion of all the voters who opposed the container control bill.
A random sample of 87 airline pilots had an average yearly income of $99,400 with a standard deviation of $12,000.
- If we want to determine a 95% confidence interval for the average yearly income, what is the value of t?
- Develop a 95% confidence interval for the average yearly income of all pilots.
In order to determine the average weight of carry-on luggage by passengers in airplanes, a sample of 25 pieces of carry-on luggage was collected and weighed. The average weight was 18 pounds. Assume that we know the standard deviation of the population to be 7.5 pounds.
- Determine a 97% confidence interval estimate for the mean weight of the carry-on luggage.
- Determine a 95% confidence interval estimate for the mean weight of the carry-on luggage.
A statistician employed by a consumer testing organization reports that at 95% confidence he has determined that the true average content of the Uncola soft drinks is between 11.7 to 12.3 ounces. He further reports that his sample revealed an average content of 12 ounces, but he forgot to report the size of the sample he had selected. Assuming the standard deviation of the population is 1.28, determine the size of the sample.
|Grading Criteria Assignments||Maximum Points|
|Meets or exceeds established assignment criteria||40|
|Demonstrates an understanding of lesson concepts||20|
|Clearly presents well-reasoned ideas and concepts||30|
|Uses proper mechanics, punctuation, sentence structure, and spelling||10|